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-1y^2=2y+3
We move all terms to the left:
-1y^2-(2y+3)=0
We get rid of parentheses
-1y^2-2y-3=0
a = -1; b = -2; c = -3;
Δ = b2-4ac
Δ = -22-4·(-1)·(-3)
Δ = -8
Delta is less than zero, so there is no solution for the equation
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